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3312458045143 = 13873129183881
BaseRepresentation
bin110000001100111101111…
…000101001011011010111
3102201200000220012120100121
4300030331320221123113
5413232403224421033
611013415555452411
7461213540550652
oct60147570513327
912650026176317
103312458045143
111067895235755
12455b875b7107
131b0495678b50
14b647680a899
155b2709a062d
hex3033de296d7

3312458045143 has 8 divisors (see below), whose sum is σ = 3567671206736. Its totient is φ = 3057303268800.

The previous prime is 3312458045089. The next prime is 3312458045159. The reversal of 3312458045143 is 3415408542133.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3312458045143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3312458045143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3312458045443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14478438 + ... + 14705443.

It is an arithmetic number, because the mean of its divisors is an integer number (445958900842).

Almost surely, 23312458045143 is an apocalyptic number.

3312458045143 is a deficient number, since it is larger than the sum of its proper divisors (255213161593).

3312458045143 is a wasteful number, since it uses less digits than its factorization.

3312458045143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29192625.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 3312458045143 in words is "three trillion, three hundred twelve billion, four hundred fifty-eight million, forty-five thousand, one hundred forty-three".

Divisors: 1 13 8731 113503 29183881 379390453 254804465011 3312458045143