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3313001425889 = 17194882436817
BaseRepresentation
bin110000001101011110010…
…001011110101111100001
3102201201102202200011121102
4300031132101132233201
5413240011331112024
611013545530204145
7461233156323251
oct60153621365741
912651382604542
103313001425889
111068043a31751
124560b9583655
131b055110c50c
14b64c8a55961
155b2a35371ae
hex3035e45ebe1

3313001425889 has 4 divisors (see below), whose sum is σ = 3507883862724. Its totient is φ = 3118118989056.

The previous prime is 3313001425873. The next prime is 3313001425901. The reversal of 3313001425889 is 9885241003133.

3313001425889 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2102964025600 + 1210037400289 = 1450160^2 + 1100017^2 .

It is a cyclic number.

It is not a de Polignac number, because 3313001425889 - 24 = 3313001425873 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3313001425859) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97441218392 + ... + 97441218425.

It is an arithmetic number, because the mean of its divisors is an integer number (876970965681).

Almost surely, 23313001425889 is an apocalyptic number.

It is an amenable number.

3313001425889 is a deficient number, since it is larger than the sum of its proper divisors (194882436835).

3313001425889 is a wasteful number, since it uses less digits than its factorization.

3313001425889 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194882436834.

The product of its (nonzero) digits is 622080, while the sum is 47.

The spelling of 3313001425889 in words is "three trillion, three hundred thirteen billion, one million, four hundred twenty-five thousand, eight hundred eighty-nine".

Divisors: 1 17 194882436817 3313001425889