331333414112042 has 4 divisors (see below), whose sum is σ = 497000121168066. Its totient is φ = 165666707056020.

The previous prime is 331333414112021. The next prime is 331333414112059. The reversal of 331333414112042 is 240211414333133.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 311042992960921 + 20290421151121 = 17636411^2 + 4504489^2 .

It is a junction number, because it is equal to n+sod(n) for n = 331333414111993 and 331333414112011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82833353528009 + ... + 82833353528012.

Almost surely, 2^{331333414112042} is an apocalyptic number.

331333414112042 is a deficient number, since it is larger than the sum of its proper divisors (165666707056024).

331333414112042 is a wasteful number, since it uses less digits than its factorization.

331333414112042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165666707056023.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 331333414112042 its reverse (240211414333133), we get a palindrome (571544828445175).

The spelling of 331333414112042 in words is "three hundred thirty-one trillion, three hundred thirty-three billion, four hundred fourteen million, one hundred twelve thousand, forty-two".