Base | Representation |
---|---|
bin | 110000001101110010101… |
… | …100011100110110010111 |
3 | 102201202022122100210021122 |
4 | 300031302230130312113 |
5 | 413241212033242333 |
6 | 11014043525434155 |
7 | 461244516440231 |
oct | 60156254346627 |
9 | 12652278323248 |
10 | 3313344040343 |
11 | 10681aa371a97 |
12 | 45619426b95b |
13 | 1b05a70aab6c |
14 | b651c35d251 |
15 | 5b2c3662798 |
hex | 30372b1cd97 |
3313344040343 has 4 divisors (see below), whose sum is σ = 3314568034200. Its totient is φ = 3312120046488.
The previous prime is 3313344040339. The next prime is 3313344040361. The reversal of 3313344040343 is 3430404433133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3313344040343 - 22 = 3313344040339 is a prime.
It is a super-2 number, since 2×33133440403432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3313344040043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611992868 + ... + 611998281.
It is an arithmetic number, because the mean of its divisors is an integer number (828642008550).
Almost surely, 23313344040343 is an apocalyptic number.
3313344040343 is a deficient number, since it is larger than the sum of its proper divisors (1223993857).
3313344040343 is a wasteful number, since it uses less digits than its factorization.
3313344040343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1223993856.
The product of its (nonzero) digits is 186624, while the sum is 35.
Adding to 3313344040343 its reverse (3430404433133), we get a palindrome (6743748473476).
The spelling of 3313344040343 in words is "three trillion, three hundred thirteen billion, three hundred forty-four million, forty thousand, three hundred forty-three".
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