Base | Representation |
---|---|
bin | 100101101111111010001111… |
… | …0001111101011011110110011 |
3 | 1121112122201121211220101112110 |
4 | 1023133310132033223132303 |
5 | 322010121143313110303 |
6 | 3134105044245500403 |
7 | 126640052026046625 |
oct | 11337643617533663 |
9 | 1545581554811473 |
10 | 332040134113203 |
11 | 9688648049065a |
12 | 312a7729111703 |
13 | 11337333b866b9 |
14 | 5bdcb84990c15 |
15 | 285c1d4c8e703 |
hex | 12dfd1e3eb7b3 |
332040134113203 has 16 divisors (see below), whose sum is σ = 458039223280800. Its totient is φ = 213702328224000.
The previous prime is 332040134113199. The next prime is 332040134113213. The reversal of 332040134113203 is 302311431040233.
It is not a de Polignac number, because 332040134113203 - 22 = 332040134113199 is a prime.
It is a super-2 number, since 2×3320401341132032 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (332040134113213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 219372298 + ... + 220880703.
It is an arithmetic number, because the mean of its divisors is an integer number (28627451455050).
Almost surely, 2332040134113203 is an apocalyptic number.
332040134113203 is a deficient number, since it is larger than the sum of its proper divisors (125999089167597).
332040134113203 is a wasteful number, since it uses less digits than its factorization.
332040134113203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440261702.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 332040134113203 its reverse (302311431040233), we get a palindrome (634351565153436).
The spelling of 332040134113203 in words is "three hundred thirty-two trillion, forty billion, one hundred thirty-four million, one hundred thirteen thousand, two hundred three".
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