Base | Representation |
---|---|
bin | 100101110000011100001010… |
… | …1011101111110101100111001 |
3 | 1121112220200201002101120102021 |
4 | 1023200320111131332230321 |
5 | 322012314411313423113 |
6 | 3134202335002434441 |
7 | 126645241530030625 |
oct | 11340702535765471 |
9 | 1545820632346367 |
10 | 332113001311033 |
11 | 96904373087908 |
12 | 312b9884202a21 |
13 | 113411773284c7 |
14 | 5c024d82c0185 |
15 | 285e04be6048d |
hex | 12e0e1577eb39 |
332113001311033 has 8 divisors (see below), whose sum is σ = 355130734077000. Its totient is φ = 309482121196800.
The previous prime is 332113001310953. The next prime is 332113001311061. The reversal of 332113001311033 is 330113100311233.
It can be written as a sum of positive squares in 4 ways, for example, as 153981990466704 + 178131010844329 = 12408948^2 + 13346573^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-332113001311033 is a prime.
It is a super-2 number, since 2×3321130013110332 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332113001310989 and 332113001311007.
It is not an unprimeable number, because it can be changed into a prime (332113001311733) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 96713161158 + ... + 96713164591.
It is an arithmetic number, because the mean of its divisors is an integer number (44391341759625).
Almost surely, 2332113001311033 is an apocalyptic number.
It is an amenable number.
332113001311033 is a deficient number, since it is larger than the sum of its proper divisors (23017732765967).
332113001311033 is a wasteful number, since it uses less digits than its factorization.
332113001311033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 193426325867.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 332113001311033 its reverse (330113100311233), we get a palindrome (662226101622266).
The spelling of 332113001311033 in words is "three hundred thirty-two trillion, one hundred thirteen billion, one million, three hundred eleven thousand, thirty-three".
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