Base | Representation |
---|---|
bin | 110000010101001101101… |
… | …100000000110100011011 |
3 | 102202111220000120010022021 |
4 | 300111031230000310123 |
5 | 413404022123300011 |
6 | 11021442402235311 |
7 | 461646143366362 |
oct | 60251554006433 |
9 | 12674800503267 |
10 | 3321313103131 |
11 | 10706197298a1 |
12 | 457839055b37 |
13 | 1b12770ab52a |
14 | b6a768927d9 |
15 | 5b5dd09b471 |
hex | 3054db00d1b |
3321313103131 has 6 divisors (see below), whose sum is σ = 3439790384732. Its totient is φ = 3206785064280.
The previous prime is 3321313103123. The next prime is 3321313103203. The reversal of 3321313103131 is 1313013131233.
It is not a de Polignac number, because 3321313103131 - 23 = 3321313103123 is a prime.
It is a super-2 number, since 2×33213131031312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3321313103096 and 3321313103105.
It is not an unprimeable number, because it can be changed into a prime (3321313103831) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1974620505 + ... + 1974622186.
Almost surely, 23321313103131 is an apocalyptic number.
3321313103131 is a deficient number, since it is larger than the sum of its proper divisors (118477281601).
3321313103131 is an equidigital number, since it uses as much as digits as its factorization.
3321313103131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3949242749 (or 3949242720 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 3321313103131 its reverse (1313013131233), we get a palindrome (4634326234364).
The spelling of 3321313103131 in words is "three trillion, three hundred twenty-one billion, three hundred thirteen million, one hundred three thousand, one hundred thirty-one".
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