Base | Representation |
---|---|
bin | 110000010101001111100… |
… | …011000100101010111001 |
3 | 102202111222012021210121220 |
4 | 300111033203010222321 |
5 | 413404103121022131 |
6 | 11021445435222253 |
7 | 461650002600315 |
oct | 60251743045271 |
9 | 12674865253556 |
10 | 3321344314041 |
11 | 1070635307036 |
12 | 4578475a7989 |
13 | 1b12806b8720 |
14 | b6a7aa98b45 |
15 | 5b5e0bb3e96 |
hex | 3054f8c4ab9 |
3321344314041 has 32 divisors (see below), whose sum is σ = 4776656855040. Its totient is φ = 2040670857024.
The previous prime is 3321344313971. The next prime is 3321344314061. The reversal of 3321344314041 is 1404134431233.
It is not a de Polignac number, because 3321344314041 - 211 = 3321344311993 is a prime.
It is a super-2 number, since 2×33213443140412 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3321344313993 and 3321344314011.
It is not an unprimeable number, because it can be changed into a prime (3321344314061) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 229003596 + ... + 229018098.
It is an arithmetic number, because the mean of its divisors is an integer number (149270526720).
Almost surely, 23321344314041 is an apocalyptic number.
It is an amenable number.
3321344314041 is a deficient number, since it is larger than the sum of its proper divisors (1455312540999).
3321344314041 is a wasteful number, since it uses less digits than its factorization.
3321344314041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23405.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 3321344314041 its reverse (1404134431233), we get a palindrome (4725478745274).
The spelling of 3321344314041 in words is "three trillion, three hundred twenty-one billion, three hundred forty-four million, three hundred fourteen thousand, forty-one".
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