Base | Representation |
---|---|
bin | 110000011110011011000… |
… | …000000010000000110010 |
3 | 102210110102001202011222011 |
4 | 300132123000002000302 |
5 | 414034244213143442 |
6 | 11030155431433134 |
7 | 462446146631023 |
oct | 60363300020062 |
9 | 12713361664864 |
10 | 3331200131122 |
11 | 10748326a2306 |
12 | 4597382257aa |
13 | 1b2191562956 |
14 | b7333a08c4a |
15 | 5b9bb091117 |
hex | 3079b002032 |
3331200131122 has 4 divisors (see below), whose sum is σ = 4996800196686. Its totient is φ = 1665600065560.
The previous prime is 3331200131069. The next prime is 3331200131179. The reversal of 3331200131122 is 2211310021333.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3285660144321 + 45539986801 = 1812639^2 + 213401^2 .
It is a super-2 number, since 2×33312001311222 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3331200131093 and 3331200131102.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 832800032779 + ... + 832800032782.
Almost surely, 23331200131122 is an apocalyptic number.
3331200131122 is a deficient number, since it is larger than the sum of its proper divisors (1665600065564).
3331200131122 is a wasteful number, since it uses less digits than its factorization.
3331200131122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1665600065563.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 3331200131122 its reverse (2211310021333), we get a palindrome (5542510152455).
The spelling of 3331200131122 in words is "three trillion, three hundred thirty-one billion, two hundred million, one hundred thirty-one thousand, one hundred twenty-two".
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