Base | Representation |
---|---|
bin | 110000011110011011000… |
… | …000010011000110010000 |
3 | 102210110102001212201222002 |
4 | 300132123000103012100 |
5 | 414034244222413404 |
6 | 11030155433133132 |
7 | 462446150342036 |
oct | 60363300230620 |
9 | 12713361781862 |
10 | 3331200201104 |
11 | 107483273a946 |
12 | 45973825a1a8 |
13 | 1b2191588769 |
14 | b7333a26556 |
15 | 5b9bb0a6c1e |
hex | 3079b013190 |
3331200201104 has 20 divisors (see below), whose sum is σ = 6461679211776. Its totient is φ = 1663670081952.
The previous prime is 3331200201071. The next prime is 3331200201191. The reversal of 3331200201104 is 4011020021333.
It is a super-2 number, since 2×33312002011042 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120611924 + ... + 120639539.
Almost surely, 23331200201104 is an apocalyptic number.
It is an amenable number.
3331200201104 is a deficient number, since it is larger than the sum of its proper divisors (3130479010672).
3331200201104 is a wasteful number, since it uses less digits than its factorization.
3331200201104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241252334 (or 241252328 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 3331200201104 its reverse (4011020021333), we get a palindrome (7342220222437).
The spelling of 3331200201104 in words is "three trillion, three hundred thirty-one billion, two hundred million, two hundred one thousand, one hundred four".
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