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33312130000034 = 279892368946807
BaseRepresentation
bin1111001001100000101011…
…01011001110010010100010
311100221121102121121220112212
413210300111223032102202
513331241220240000114
6154503214203522122
710005502431023354
oct744602553162242
9140847377556485
1033312130000034
11a68365aa37646
1238a0144b29342
131578421b4b062
1483245c3a30d4
153cb7d1a7ab3e
hex1e4c15ace4a2

33312130000034 has 16 divisors (see below), whose sum is σ = 51169251052800. Its totient is φ = 16260450876384.

The previous prime is 33312130000031. The next prime is 33312130000081. The reversal of 33312130000034 is 43000003121333.

It is a super-2 number, since 2×333121300000342 (a number of 28 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 33312129999964 and 33312130000009.

It is not an unprimeable number, because it can be changed into a prime (33312130000031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1184459342 + ... + 1184487465.

It is an arithmetic number, because the mean of its divisors is an integer number (3198078190800).

Almost surely, 233312130000034 is an apocalyptic number.

33312130000034 is a deficient number, since it is larger than the sum of its proper divisors (17857121052766).

33312130000034 is a wasteful number, since it uses less digits than its factorization.

33312130000034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2368946977.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 33312130000034 its reverse (43000003121333), we get a palindrome (76312133121367).

The spelling of 33312130000034 in words is "thirty-three trillion, three hundred twelve billion, one hundred thirty million, thirty-four", and thus it is an aban number.

Divisors: 1 2 79 89 158 178 7031 14062 2368946807 4737893614 187146797753 210836265823 374293595506 421672531646 16656065000017 33312130000034