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3331245040341 = 325121432064379
BaseRepresentation
bin110000011110011101101…
…011010110001011010101
3102210110112012020210211120
4300132131223112023111
5414034342212242331
611030204114154153
7462450233433501
oct60363553261325
912713465223746
103331245040341
111074855a86269
1245974b282959
131b219a957b5a
14b7339979301
155b9beeb2796
hex3079dad62d5

3331245040341 has 16 divisors (see below), whose sum is σ = 4461438965760. Its totient is φ = 2210948838000.

The previous prime is 3331245040339. The next prime is 3331245040349. The reversal of 3331245040341 is 1430405421333.

It is not a de Polignac number, because 3331245040341 - 21 = 3331245040339 is a prime.

It is a super-2 number, since 2×33312450403412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3331245040349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 581490 + ... + 2645868.

It is an arithmetic number, because the mean of its divisors is an integer number (278839935360).

Almost surely, 23331245040341 is an apocalyptic number.

It is an amenable number.

3331245040341 is a deficient number, since it is larger than the sum of its proper divisors (1130193925419).

3331245040341 is a wasteful number, since it uses less digits than its factorization.

3331245040341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2066776.

The product of its (nonzero) digits is 51840, while the sum is 33.

The spelling of 3331245040341 in words is "three trillion, three hundred thirty-one billion, two hundred forty-five million, forty thousand, three hundred forty-one".

Divisors: 1 3 251 753 2143 6429 537893 1613679 2064379 6193137 518159129 1554477387 4423964197 13271892591 1110415013447 3331245040341