Base | Representation |
---|---|
bin | 110000011110100111110… |
… | …000101101110101001111 |
3 | 102210110221222121000211222 |
4 | 300132213300231311033 |
5 | 414040214020020421 |
6 | 11030233000233555 |
7 | 462454356435125 |
oct | 60364760556517 |
9 | 12713858530758 |
10 | 3331414220111 |
11 | 107493252855a |
12 | 459797a6b8bb |
13 | 1b21c6a10a23 |
14 | b7354217915 |
15 | 5b9cec7ecab |
hex | 307a7c2dd4f |
3331414220111 has 4 divisors (see below), whose sum is σ = 3331791469824. Its totient is φ = 3331036970400.
The previous prime is 3331414220107. The next prime is 3331414220117. The reversal of 3331414220111 is 1110224141333.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3331414220111 - 22 = 3331414220107 is a prime.
It is a super-2 number, since 2×33314142201112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3331414220117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188611610 + ... + 188629271.
It is an arithmetic number, because the mean of its divisors is an integer number (832947867456).
Almost surely, 23331414220111 is an apocalyptic number.
3331414220111 is a deficient number, since it is larger than the sum of its proper divisors (377249713).
3331414220111 is an equidigital number, since it uses as much as digits as its factorization.
3331414220111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377249712.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 3331414220111 its reverse (1110224141333), we get a palindrome (4441638361444).
The spelling of 3331414220111 in words is "three trillion, three hundred thirty-one billion, four hundred fourteen million, two hundred twenty thousand, one hundred eleven".
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