Base | Representation |
---|---|
bin | 11111000010010010… |
… | …100111111011110101 |
3 | 10012000102210121022111 |
4 | 133002102213323311 |
5 | 1021222023330031 |
6 | 23150430131021 |
7 | 2256545002516 |
oct | 370222477365 |
9 | 105012717274 |
10 | 33324433141 |
11 | 1315085693a |
12 | 6560350a71 |
13 | 31b10505bc |
14 | 1881b84a0d |
15 | d009061b1 |
hex | 7c24a7ef5 |
33324433141 has 8 divisors (see below), whose sum is σ = 35290975104. Its totient is φ = 31358589120.
The previous prime is 33324433139. The next prime is 33324433151. The reversal of 33324433141 is 14133442333.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 33324433141 - 21 = 33324433139 is a prime.
It is a super-4 number, since 4×333244331414 (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33324433151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74535 + ... + 268708.
It is an arithmetic number, because the mean of its divisors is an integer number (4411371888).
Almost surely, 233324433141 is an apocalyptic number.
It is an amenable number.
33324433141 is a deficient number, since it is larger than the sum of its proper divisors (1966541963).
33324433141 is a wasteful number, since it uses less digits than its factorization.
33324433141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 348971.
The product of its digits is 31104, while the sum is 31.
Adding to 33324433141 its reverse (14133442333), we get a palindrome (47457875474).
The spelling of 33324433141 in words is "thirty-three billion, three hundred twenty-four million, four hundred thirty-three thousand, one hundred forty-one".
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