33340044341141 has 4 divisors (see below), whose sum is σ = 34789611486432. Its totient is φ = 31890477195852.

The previous prime is 33340044341119. The next prime is 33340044341171. The reversal of 33340044341141 is 14114344004333.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33340044341141 is a prime.

It is a super-2 number, since 2×33340044341141² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33340044341171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 724783572611 + ... + 724783572656.

It is an arithmetic number, because the mean of its divisors is an integer number (8697402871608).

Almost surely, 2^{33340044341141} is an apocalyptic number.

It is an amenable number.

33340044341141 is a deficient number, since it is larger than the sum of its proper divisors (1449567145291).

33340044341141 is a wasteful number, since it uses less digits than its factorization.

33340044341141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1449567145290.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 33340044341141 its reverse (14114344004333), we get a palindrome (47454388345474).

The spelling of 33340044341141 in words is "thirty-three trillion, three hundred forty billion, forty-four million, three hundred forty-one thousand, one hundred forty-one".