Base | Representation |
---|---|
bin | 110000100001101100010… |
… | …111000100110000000101 |
3 | 102210210110212002120212221 |
4 | 300201230113010300011 |
5 | 414113442412003142 |
6 | 11031540144212341 |
7 | 462632200332442 |
oct | 60415427046005 |
9 | 12723425076787 |
10 | 3334712609797 |
11 | 1076275372548 |
12 | 45a35860a0b1 |
13 | 1b260117b0ba |
14 | b75882d49c9 |
15 | 5bb24615767 |
hex | 3086c5c4c05 |
3334712609797 has 12 divisors (see below), whose sum is σ = 3495278404800. Its totient is φ = 3180930615632.
The previous prime is 3334712609783. The next prime is 3334712609803. The reversal of 3334712609797 is 7979062174333.
It is a de Polignac number, because none of the positive numbers 2k-3334712609797 is a prime.
It is a super-2 number, since 2×33347126097972 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3334712609707) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23816797 + ... + 23956402.
It is an arithmetic number, because the mean of its divisors is an integer number (291273200400).
Almost surely, 23334712609797 is an apocalyptic number.
It is an amenable number.
3334712609797 is a deficient number, since it is larger than the sum of its proper divisors (160565795003).
3334712609797 is an equidigital number, since it uses as much as digits as its factorization.
3334712609797 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47773340 (or 47773311 counting only the distinct ones).
The product of its (nonzero) digits is 36006768, while the sum is 61.
The spelling of 3334712609797 in words is "three trillion, three hundred thirty-four billion, seven hundred twelve million, six hundred nine thousand, seven hundred ninety-seven".
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