Base | Representation |
---|---|
bin | 100101111110001111100111… |
… | …1010101000110111011000010 |
3 | 1121210122001201010200002110022 |
4 | 1023330133033111012323002 |
5 | 322234410342213000442 |
6 | 3142214100113333442 |
7 | 130232304062622503 |
oct | 11374371725067302 |
9 | 1553561633602408 |
10 | 334010200125122 |
11 | 97475a26385114 |
12 | 315654b8267282 |
13 | 1144b046929191 |
14 | 5c6a273a9abaa |
15 | 2893589d323d2 |
hex | 12fc7cf546ec2 |
334010200125122 has 4 divisors (see below), whose sum is σ = 501015300187686. Its totient is φ = 167005100062560.
The previous prime is 334010200125101. The next prime is 334010200125167. The reversal of 334010200125122 is 221521002010433.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 309124578999721 + 24885621125401 = 17581939^2 + 4988549^2 .
It is a super-2 number, since 2×3340102001251222 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 334010200125091 and 334010200125100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83502550031279 + ... + 83502550031282.
Almost surely, 2334010200125122 is an apocalyptic number.
334010200125122 is a deficient number, since it is larger than the sum of its proper divisors (167005100062564).
334010200125122 is a wasteful number, since it uses less digits than its factorization.
334010200125122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167005100062563.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 334010200125122 its reverse (221521002010433), we get a palindrome (555531202135555).
The spelling of 334010200125122 in words is "three hundred thirty-four trillion, ten billion, two hundred million, one hundred twenty-five thousand, one hundred twenty-two".
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