334011440004434 has 4 divisors (see below), whose sum is σ = 501017160006654. Its totient is φ = 167005720002216.

The previous prime is 334011440004401. The next prime is 334011440004481. The reversal of 334011440004434 is 434400044110433.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 291237263205625 + 42774176798809 = 17065675^2 + 6540197^2 .

It is a super-2 number, since 2×334011440004434² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334011440004394 and 334011440004403.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83502860001107 + ... + 83502860001110.

Almost surely, 2^{334011440004434} is an apocalyptic number.

334011440004434 is a deficient number, since it is larger than the sum of its proper divisors (167005720002220).

334011440004434 is a wasteful number, since it uses less digits than its factorization.

334011440004434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167005720002219.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 334011440004434 its reverse (434400044110433), we get a palindrome (768411484114867).

The spelling of 334011440004434 in words is "three hundred thirty-four trillion, eleven billion, four hundred forty million, four thousand, four hundred thirty-four".