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334013110114 = 2167006555057
BaseRepresentation
bin1001101110001001011…
…10111001011101100010
31011221010221121001021011
410313010232321131202
520433024324010424
6413235444051134
733063104406565
oct4670456713542
91157127531234
10334013110114
11119721769362
1254898393aaa
1325660755778
14122485544dc
158a4d79c694
hex4dc4bb9762

334013110114 has 4 divisors (see below), whose sum is σ = 501019665174. Its totient is φ = 167006555056.

The previous prime is 334013110073. The next prime is 334013110133. The reversal of 334013110114 is 411011310433.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411011310433 = 937438646009.

It can be written as a sum of positive squares in only one way, i.e., 191435126089 + 142577984025 = 437533^2 + 377595^2 .

It is a super-2 number, since 2×3340131101142 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83503277527 + ... + 83503277530.

Almost surely, 2334013110114 is an apocalyptic number.

334013110114 is a deficient number, since it is larger than the sum of its proper divisors (167006555060).

334013110114 is a wasteful number, since it uses less digits than its factorization.

334013110114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167006555059.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 334013110114 its reverse (411011310433), we get a palindrome (745024420547).

The spelling of 334013110114 in words is "three hundred thirty-four billion, thirteen million, one hundred ten thousand, one hundred fourteen".

Divisors: 1 2 167006555057 334013110114