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334020034 = 2167010017
BaseRepresentation
bin10011111010001…
…011110111000010
3212021111222100101
4103322023313002
51141002120114
653051113014
711164060225
oct2372136702
9767458311
10334020034
11161600217
1293a4276a
135427c7ba
143250b5bc
151e4cdd74
hex13e8bdc2

334020034 has 4 divisors (see below), whose sum is σ = 501030054. Its totient is φ = 167010016.

The previous prime is 334020031. The next prime is 334020059. The reversal of 334020034 is 430020433.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 214183225 + 119836809 = 14635^2 + 10947^2 .

It is a super-2 number, since 2×3340200342 = 223138766226722312, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334019993 and 334020020.

It is not an unprimeable number, because it can be changed into a prime (334020031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83505007 + ... + 83505010.

Almost surely, 2334020034 is an apocalyptic number.

334020034 is a deficient number, since it is larger than the sum of its proper divisors (167010020).

334020034 is a wasteful number, since it uses less digits than its factorization.

334020034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167010019.

The product of its (nonzero) digits is 864, while the sum is 19.

The square root of 334020034 is about 18276.2149801320. The cubic root of 334020034 is about 693.8370794137.

Adding to 334020034 its reverse (430020433), we get a palindrome (764040467).

The spelling of 334020034 in words is "three hundred thirty-four million, twenty thousand, thirty-four".

Divisors: 1 2 167010017 334020034