3340244121 has 4 divisors (see below), whose sum is σ = 4453658832. Its totient is φ = 2226829412.

The previous prime is 3340244093. The next prime is 3340244143. The reversal of 3340244121 is 1214420433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3340244121 - 2⁷ = 3340243993 is a prime.

It is a super-2 number, since 2×3340244121² = 22314461575750125282, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3340244091 and 3340244100.

It is not an unprimeable number, because it can be changed into a prime (3340244191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556707351 + ... + 556707356.

It is an arithmetic number, because the mean of its divisors is an integer number (1113414708).

Almost surely, 2^3340244121 is an apocalyptic number.

It is an amenable number.

3340244121 is a deficient number, since it is larger than the sum of its proper divisors (1113414711).

3340244121 is a wasteful number, since it uses less digits than its factorization.

3340244121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1113414710.

The product of its (nonzero) digits is 2304, while the sum is 24.

The square root of 3340244121 is about 57794.8451075007. The cubic root of 3340244121 is about 1494.8332041369.

Adding to 3340244121 its reverse (1214420433), we get a palindrome (4554664554).

The spelling of 3340244121 in words is "three billion, three hundred forty million, two hundred forty-four thousand, one hundred twenty-one".