3340321413439 has 4 divisors (see below), whose sum is σ = 3516127803640. Its totient is φ = 3164515023240.

The previous prime is 3340321413431. The next prime is 3340321413449. The reversal of 3340321413439 is 9343141230433.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3340321413439 - 2³ = 3340321413431 is a prime.

It is a super-3 number, since 3×3340321413439³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3340321413431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87903195072 + ... + 87903195109.

It is an arithmetic number, because the mean of its divisors is an integer number (879031950910).

Almost surely, 2^{3340321413439} is an apocalyptic number.

3340321413439 is a deficient number, since it is larger than the sum of its proper divisors (175806390201).

3340321413439 is a wasteful number, since it uses less digits than its factorization.

3340321413439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175806390200.

The product of its (nonzero) digits is 279936, while the sum is 40.

It can be divided in two parts, 334032 and 1413439, that added together give a palindrome (1747471).

The spelling of 3340321413439 in words is "three trillion, three hundred forty billion, three hundred twenty-one million, four hundred thirteen thousand, four hundred thirty-nine".