Base | Representation |
---|---|
bin | 1001101110001100101… |
… | …10000000100011111111 |
3 | 1011221012211110022100012 |
4 | 10313012112000203333 |
5 | 20433103233440111 |
6 | 413242251253435 |
7 | 33063553225163 |
oct | 4670626004377 |
9 | 1157184408305 |
10 | 334040140031 |
11 | 119735a50334 |
12 | 548a544a27b |
13 | 2566622a8c0 |
14 | 1224bd8cca3 |
15 | 8a50d3b48b |
hex | 4dc65808ff |
334040140031 has 4 divisors (see below), whose sum is σ = 359735535432. Its totient is φ = 308344744632.
The previous prime is 334040140013. The next prime is 334040140039. The reversal of 334040140031 is 130041040433.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 334040140031 - 214 = 334040123647 is a prime.
It is a super-2 number, since 2×3340401400312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 334040139979 and 334040140006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (334040140039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12847697681 + ... + 12847697706.
It is an arithmetic number, because the mean of its divisors is an integer number (89933883858).
Almost surely, 2334040140031 is an apocalyptic number.
334040140031 is a deficient number, since it is larger than the sum of its proper divisors (25695395401).
334040140031 is a wasteful number, since it uses less digits than its factorization.
334040140031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25695395400.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 334040140031 its reverse (130041040433), we get a palindrome (464081180464).
The spelling of 334040140031 in words is "three hundred thirty-four billion, forty million, one hundred forty thousand, thirty-one".
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