3340550433 has 8 divisors (see below), whose sum is σ = 4858982496. Its totient is φ = 2024576000.

The previous prime is 3340550419. The next prime is 3340550449.

3340550433 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3340550433 - 2¹⁰ = 3340549409 is a prime.

It is a super-2 number, since 2×3340550433² = 22318554390832974978, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3340550433.

It is not an unprimeable number, because it can be changed into a prime (3340550413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50614368 + ... + 50614433.

It is an arithmetic number, because the mean of its divisors is an integer number (607372812).

Almost surely, 2^3340550433 is an apocalyptic number.

3340550433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

3340550433 is a deficient number, since it is larger than the sum of its proper divisors (1518432063).

3340550433 is a wasteful number, since it uses less digits than its factorization.

3340550433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101228815.

The product of its (nonzero) digits is 32400, while the sum is 30.

The square root of 3340550433 is about 57797.4950408753. The cubic root of 3340550433 is about 1494.8788965410.

It can be divided in two parts, 33405 and 50433, that added together give a palindrome (83838).

The spelling of 3340550433 in words is "three billion, three hundred forty million, five hundred fifty thousand, four hundred thirty-three".