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3340704070735 = 5668140814147
BaseRepresentation
bin110000100111010001011…
…110101011110001001111
3102211100221102002100011121
4300213101132223301033
5414213230220230420
611034410454101411
7463233522034543
oct60472136536117
912740842070147
103340704070735
11107886a3a0859
1245b54b04a867
131b3047547265
14b7995d1da23
155bd756132aa
hex309d17abc4f

3340704070735 has 4 divisors (see below), whose sum is σ = 4008844884888. Its totient is φ = 2672563256584.

The previous prime is 3340704070699. The next prime is 3340704070747. The reversal of 3340704070735 is 5370704070433.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3340704070735 - 225 = 3340670516303 is a prime.

It is a super-2 number, since 2×33407040707352 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3340704070691 and 3340704070700.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334070407069 + ... + 334070407078.

It is an arithmetic number, because the mean of its divisors is an integer number (1002211221222).

Almost surely, 23340704070735 is an apocalyptic number.

3340704070735 is a deficient number, since it is larger than the sum of its proper divisors (668140814153).

3340704070735 is an equidigital number, since it uses as much as digits as its factorization.

3340704070735 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 668140814152.

The product of its (nonzero) digits is 740880, while the sum is 43.

The spelling of 3340704070735 in words is "three trillion, three hundred forty billion, seven hundred four million, seventy thousand, seven hundred thirty-five".

Divisors: 1 5 668140814147 3340704070735