Base | Representation |
---|---|
bin | 1001101110010000011… |
… | …00100000010010111001 |
3 | 1011221021222220110201120 |
4 | 10313020030200102321 |
5 | 20433134211444001 |
6 | 413245321135453 |
7 | 33064411241604 |
oct | 4671014402271 |
9 | 1157258813646 |
10 | 334071203001 |
11 | 119751537408 |
12 | 548b392a589 |
13 | 2566c7b5663 |
14 | 1225215733b |
15 | 8a53925236 |
hex | 4dc83204b9 |
334071203001 has 4 divisors (see below), whose sum is σ = 445428270672. Its totient is φ = 222714135332.
The previous prime is 334071202957. The next prime is 334071203009. The reversal of 334071203001 is 100302170433.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 334071203001 - 219 = 334070678713 is a prime.
It is a super-2 number, since 2×3340712030012 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (334071203009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55678533831 + ... + 55678533836.
It is an arithmetic number, because the mean of its divisors is an integer number (111357067668).
Almost surely, 2334071203001 is an apocalyptic number.
It is an amenable number.
334071203001 is a deficient number, since it is larger than the sum of its proper divisors (111357067671).
334071203001 is a wasteful number, since it uses less digits than its factorization.
334071203001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111357067670.
The product of its (nonzero) digits is 1512, while the sum is 24.
Adding to 334071203001 its reverse (100302170433), we get a palindrome (434373373434).
The spelling of 334071203001 in words is "three hundred thirty-four billion, seventy-one million, two hundred three thousand, one".
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