Base | Representation |
---|---|
bin | 1001101110011000111… |
… | …11001010001100110111 |
3 | 1011221111000101101220222 |
4 | 10313030133022030313 |
5 | 20433311124431403 |
6 | 413300412244555 |
7 | 33066244232534 |
oct | 4671437121467 |
9 | 1157430341828 |
10 | 334143202103 |
11 | 1197891433a7 |
12 | 54913a7075b |
13 | 256816a4089 |
14 | 1225b939d8b |
15 | 8a59de8338 |
hex | 4dcc7ca337 |
334143202103 has 4 divisors (see below), whose sum is σ = 334166183400. Its totient is φ = 334120220808.
The previous prime is 334143202091. The next prime is 334143202111. The reversal of 334143202103 is 301202341433.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 334143202103 - 24 = 334143202087 is a prime.
It is a super-2 number, since 2×3341432021032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (334143201103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11468825 + ... + 11497922.
It is an arithmetic number, because the mean of its divisors is an integer number (83541545850).
Almost surely, 2334143202103 is an apocalyptic number.
334143202103 is a deficient number, since it is larger than the sum of its proper divisors (22981297).
334143202103 is a wasteful number, since it uses less digits than its factorization.
334143202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22981296.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 334143202103 its reverse (301202341433), we get a palindrome (635345543536).
The spelling of 334143202103 in words is "three hundred thirty-four billion, one hundred forty-three million, two hundred two thousand, one hundred three".
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