3341440441433 has 4 divisors (see below), whose sum is σ = 3352324612560. Its totient is φ = 3330556270308.

The previous prime is 3341440441421. The next prime is 3341440441457.

3341440441433 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3341440441433 - 2¹⁰ = 3341440440409 is a prime.

It is a super-2 number, since 2×3341440441433² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3341440441483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5442085103 + ... + 5442085716.

It is an arithmetic number, because the mean of its divisors is an integer number (838081153140).

Almost surely, 2^{3341440441433} is an apocalyptic number.

It is an amenable number.

3341440441433 is a deficient number, since it is larger than the sum of its proper divisors (10884171127).

3341440441433 is a wasteful number, since it uses less digits than its factorization.

3341440441433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10884171126.

The product of its (nonzero) digits is 331776, while the sum is 38.

It can be divided in two parts, 3341440 and 441433, that added together give a palindrome (3782873).

The spelling of 3341440441433 in words is "three trillion, three hundred forty-one billion, four hundred forty million, four hundred forty-one thousand, four hundred thirty-three".