334145443241 has 4 divisors (see below), whose sum is σ = 334146768000. Its totient is φ = 334144118484.

The previous prime is 334145443237. The next prime is 334145443267. The reversal of 334145443241 is 142344541433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 142344541433 = 439 ⋅324247247.

It is a cyclic number.

It is not a de Polignac number, because 334145443241 - 2² = 334145443237 is a prime.

It is a super-2 number, since 2×334145443241² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 334145443195 and 334145443204.

It is not an unprimeable number, because it can be changed into a prime (334145443441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153941 + ... + 831858.

It is an arithmetic number, because the mean of its divisors is an integer number (83536692000).

Almost surely, 2^334145443241 is an apocalyptic number.

It is an amenable number.

334145443241 is a deficient number, since it is larger than the sum of its proper divisors (1324759).

334145443241 is an equidigital number, since it uses as much as digits as its factorization.

334145443241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1324758.

The product of its digits is 276480, while the sum is 38.

Adding to 334145443241 its reverse (142344541433), we get a palindrome (476489984674).

The spelling of 334145443241 in words is "three hundred thirty-four billion, one hundred forty-five million, four hundred forty-three thousand, two hundred forty-one".