3343250041 has 4 divisors (see below), whose sum is σ = 3347774800. Its totient is φ = 3338725284.

The previous prime is 3343249999. The next prime is 3343250063. The reversal of 3343250041 is 1400523433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1400523433 = 1319 ⋅1061807.

It is a cyclic number.

It is not a de Polignac number, because 3343250041 - 2¹¹ = 3343247993 is a prime.

It is a super-2 number, since 2×3343250041² = 22354641673293003362, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3343249988 and 3343250015.

It is not an unprimeable number, because it can be changed into a prime (3343250081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2261271 + ... + 2262748.

It is an arithmetic number, because the mean of its divisors is an integer number (836943700).

Almost surely, 2^3343250041 is an apocalyptic number.

It is an amenable number.

3343250041 is a deficient number, since it is larger than the sum of its proper divisors (4524759).

3343250041 is an equidigital number, since it uses as much as digits as its factorization.

3343250041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4524758.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 3343250041 is about 57820.8443470000. The cubic root of 3343250041 is about 1495.2814749484.

Adding to 3343250041 its reverse (1400523433), we get a palindrome (4743773474).

The spelling of 3343250041 in words is "three billion, three hundred forty-three million, two hundred fifty thousand, forty-one".