33440113141441 has 4 divisors (see below), whose sum is σ = 33440666452272. Its totient is φ = 33439559830612.

The previous prime is 33440113141439. The next prime is 33440113141451. The reversal of 33440113141441 is 14414131104433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 33440113141441 - 2¹ = 33440113141439 is a prime.

It is a super-3 number, since 3×33440113141441³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33440113141397 and 33440113141406.

It is not an unprimeable number, because it can be changed into a prime (33440113141411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276564751 + ... + 276685636.

It is an arithmetic number, because the mean of its divisors is an integer number (8360166613068).

Almost surely, 2^{33440113141441} is an apocalyptic number.

It is an amenable number.

33440113141441 is a deficient number, since it is larger than the sum of its proper divisors (553310831).

33440113141441 is an equidigital number, since it uses as much as digits as its factorization.

33440113141441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 553310830.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 33440113141441 its reverse (14414131104433), we get a palindrome (47854244245874).

The spelling of 33440113141441 in words is "thirty-three trillion, four hundred forty billion, one hundred thirteen million, one hundred forty-one thousand, four hundred forty-one".