3345005433 has 72 divisors (see below), whose sum is σ = 5739726720. Its totient is φ = 1726401600.

The previous prime is 3345005429. The next prime is 3345005441.

3345005433 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 3345005433 - 2² = 3345005429 is a prime.

It is a super-2 number, since 2×3345005433² = 22378122693599034978, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3345005433.

It is not an unprimeable number, because it can be changed into a prime (3345005453) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3218928 + ... + 3219966.

Almost surely, 2^3345005433 is an apocalyptic number.

3345005433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

3345005433 is a deficient number, since it is larger than the sum of its proper divisors (2394721287).

3345005433 is a wasteful number, since it uses less digits than its factorization.

3345005433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1259 (or 1241 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 30.

The square root of 3345005433 is about 57836.0219327021. The cubic root of 3345005433 is about 1495.5431311064.

It can be divided in two parts, 334500 and 5433, that added together give a palindrome (339933).

The spelling of 3345005433 in words is "three billion, three hundred forty-five million, five thousand, four hundred thirty-three".