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3345642465433 = 4377805638731
BaseRepresentation
bin110000101011110111110…
…101001010100010011001
3102211211200120112210010221
4300223313311022202121
5414303333432343213
611040544505040041
7463500065510662
oct60536765124231
912754616483127
103345642465433
11107a973a50894
124604a8a86021
131b36536b62b8
14b7d03b46369
155c063e4b38d
hex30af7d4a899

3345642465433 has 4 divisors (see below), whose sum is σ = 3423448104208. Its totient is φ = 3267836826660.

The previous prime is 3345642465413. The next prime is 3345642465437.

It is a happy number.

3345642465433 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3345642465433 - 217 = 3345642334361 is a prime.

It is a super-2 number, since 2×33456424654332 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3345642465437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38902819323 + ... + 38902819408.

It is an arithmetic number, because the mean of its divisors is an integer number (855862026052).

Almost surely, 23345642465433 is an apocalyptic number.

It is an amenable number.

3345642465433 is a deficient number, since it is larger than the sum of its proper divisors (77805638775).

3345642465433 is an equidigital number, since it uses as much as digits as its factorization.

3345642465433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77805638774.

The product of its digits is 37324800, while the sum is 52.

The spelling of 3345642465433 in words is "three trillion, three hundred forty-five billion, six hundred forty-two million, four hundred sixty-five thousand, four hundred thirty-three".

Divisors: 1 43 77805638731 3345642465433