Base | Representation |
---|---|
bin | 11111001100110010… |
… | …000000101011100001 |
3 | 10012110200222022220021 |
4 | 133030302000223201 |
5 | 1022102102324441 |
6 | 23220114313441 |
7 | 2264112661141 |
oct | 371462005341 |
9 | 105420868807 |
10 | 33500433121 |
11 | 13231137271 |
12 | 65ab288881 |
13 | 320b6538bc |
14 | 189b2ba921 |
15 | d110be3d1 |
hex | 7ccc80ae1 |
33500433121 has 8 divisors (see below), whose sum is σ = 36694186920. Its totient is φ = 30442583808.
The previous prime is 33500433103. The next prime is 33500433173. The reversal of 33500433121 is 12133400533.
It can be written as a sum of positive squares in 4 ways, for example, as 2543790096 + 30956643025 = 50436^2 + 175945^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 33500433121 - 211 = 33500431073 is a prime.
It is a super-2 number, since 2×335004331212 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33500433521) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33975606 + ... + 33976591.
It is an arithmetic number, because the mean of its divisors is an integer number (4586773365).
Almost surely, 233500433121 is an apocalyptic number.
It is an amenable number.
33500433121 is a deficient number, since it is larger than the sum of its proper divisors (3193753799).
33500433121 is a wasteful number, since it uses less digits than its factorization.
33500433121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67952243.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 33500433121 its reverse (12133400533), we get a palindrome (45633833654).
The spelling of 33500433121 in words is "thirty-three billion, five hundred million, four hundred thirty-three thousand, one hundred twenty-one".
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