3354040031 has 4 divisors (see below), whose sum is σ = 3354263472. Its totient is φ = 3353816592.

The previous prime is 3354040013. The next prime is 3354040057. The reversal of 3354040031 is 1300404533.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1300404533 = 15137 ⋅85909.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3354040031 is a prime.

It is a super-2 number, since 2×3354040031² = 22499169059100961922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3354039979 and 3354040006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3354040831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87446 + ... + 119811.

It is an arithmetic number, because the mean of its divisors is an integer number (838565868).

Almost surely, 2^3354040031 is an apocalyptic number.

3354040031 is a deficient number, since it is larger than the sum of its proper divisors (223441).

3354040031 is a wasteful number, since it uses less digits than its factorization.

3354040031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 223440.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 3354040031 is about 57914.0745501471. The cubic root of 3354040031 is about 1496.8883690393. Note that the first 3 decimals are identical.

Adding to 3354040031 its reverse (1300404533), we get a palindrome (4654444564).

The spelling of 3354040031 in words is "three billion, three hundred fifty-four million, forty thousand, thirty-one".