3400014311 has 4 divisors (see below), whose sum is σ = 3509692224. Its totient is φ = 3290336400.

The previous prime is 3400014287. The next prime is 3400014313. The reversal of 3400014311 is 1134100043.

3400014311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1134100043 = 4129 ⋅274667.

It is a cyclic number.

It is not a de Polignac number, because 3400014311 - 2¹⁴ = 3399997927 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3400014311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3400014313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54838910 + ... + 54838971.

It is an arithmetic number, because the mean of its divisors is an integer number (877423056).

Almost surely, 2^3400014311 is an apocalyptic number.

3400014311 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

3400014311 is a deficient number, since it is larger than the sum of its proper divisors (109677913).

3400014311 is a wasteful number, since it uses less digits than its factorization.

3400014311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109677912.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3400014311 is about 58309.6416641365. The cubic root of 3400014311 is about 1503.6967059445.

Adding to 3400014311 its reverse (1134100043), we get a palindrome (4534114354).

The spelling of 3400014311 in words is "three billion, four hundred million, fourteen thousand, three hundred eleven".