Base | Representation |
---|---|
bin | 110001011110100110100… |
… | …110011001000100001111 |
3 | 110001001021210202021102001 |
4 | 301132212212121010033 |
5 | 421201413214310020 |
6 | 11121554011413131 |
7 | 500435666645023 |
oct | 61364646310417 |
9 | 13031253667361 |
10 | 3400114213135 |
11 | 10a0a869180a2 |
12 | 46ab6b4541a7 |
13 | 1b8824a1a183 |
14 | ba7d030a383 |
15 | 5d6a119d50a |
hex | 317a699910f |
3400114213135 has 8 divisors (see below), whose sum is σ = 4257534319200. Its totient is φ = 2601826528224.
The previous prime is 3400114213127. The next prime is 3400114213147. The reversal of 3400114213135 is 5313124110043.
3400114213135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3400114213135 - 23 = 3400114213127 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14783105160 + ... + 14783105389.
It is an arithmetic number, because the mean of its divisors is an integer number (532191789900).
Almost surely, 23400114213135 is an apocalyptic number.
3400114213135 is a deficient number, since it is larger than the sum of its proper divisors (857420106065).
3400114213135 is a wasteful number, since it uses less digits than its factorization.
3400114213135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29566210577.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 3400114213135 its reverse (5313124110043), we get a palindrome (8713238323178).
The spelling of 3400114213135 in words is "three trillion, four hundred billion, one hundred fourteen million, two hundred thirteen thousand, one hundred thirty-five".
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