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340028148703 = 1163292371581
BaseRepresentation
bin1001111001010110100…
…00011100101111011111
31012111200010221200000011
410330223100130233133
521032334201224303
6420112355144051
733365133401335
oct4745320345737
91174603850004
10340028148703
11121229030931
1255a968a5027
13260ab9885b9
1412659359b55
158ca18a616d
hex4f2b41cbdf

340028148703 has 4 divisors (see below), whose sum is σ = 340320521448. Its totient is φ = 339735775960.

The previous prime is 340028148683. The next prime is 340028148739. The reversal of 340028148703 is 307841820043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 340028148703 - 25 = 340028148671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340028148743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146184628 + ... + 146186953.

It is an arithmetic number, because the mean of its divisors is an integer number (85080130362).

Almost surely, 2340028148703 is an apocalyptic number.

340028148703 is a deficient number, since it is larger than the sum of its proper divisors (292372745).

340028148703 is a wasteful number, since it uses less digits than its factorization.

340028148703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292372744.

The product of its (nonzero) digits is 129024, while the sum is 40.

Adding to 340028148703 its reverse (307841820043), we get a palindrome (647869968746).

The spelling of 340028148703 in words is "three hundred forty billion, twenty-eight million, one hundred forty-eight thousand, seven hundred three".

Divisors: 1 1163 292371581 340028148703