Base | Representation |
---|---|
bin | 1111011101100111111110… |
… | …01000000010101010110111 |
3 | 11110101200022100200022112211 |
4 | 13232303333020002222313 |
5 | 13424102114300211203 |
6 | 200152512355554251 |
7 | 10106440010065021 |
oct | 756637710025267 |
9 | 143350270608484 |
10 | 34003241413303 |
11 | a91a76a351498 |
12 | 39920808bb987 |
13 | 15c8651946406 |
14 | 857aa0db5011 |
15 | 3de780612c6d |
hex | 1eecff202ab7 |
34003241413303 has 4 divisors (see below), whose sum is σ = 34006621131288. Its totient is φ = 33999861695320.
The previous prime is 34003241413301. The next prime is 34003241413327. The reversal of 34003241413303 is 30331414230043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34003241413303 - 21 = 34003241413301 is a prime.
It is a super-2 number, since 2×340032414133032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34003241413301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1689843901 + ... + 1689864022.
It is an arithmetic number, because the mean of its divisors is an integer number (8501655282822).
Almost surely, 234003241413303 is an apocalyptic number.
34003241413303 is a deficient number, since it is larger than the sum of its proper divisors (3379717985).
34003241413303 is a wasteful number, since it uses less digits than its factorization.
34003241413303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3379717984.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 34003241413303 its reverse (30331414230043), we get a palindrome (64334655643346).
The spelling of 34003241413303 in words is "thirty-four trillion, three billion, two hundred forty-one million, four hundred thirteen thousand, three hundred three".
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