340034120203333 has 4 divisors (see below), whose sum is σ = 344692121850028. Its totient is φ = 335376118556640.

The previous prime is 340034120203331. The next prime is 340034120203361. The reversal of 340034120203333 is 333302021430043.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131787805532769 + 208246314670564 = 11479887^2 + 14430742^2 .

It is a cyclic number.

It is not a de Polignac number, because 340034120203333 - 2¹ = 340034120203331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340034120203295 and 340034120203304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340034120203331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2329000823238 + ... + 2329000823383.

It is an arithmetic number, because the mean of its divisors is an integer number (86173030462507).

Almost surely, 2^{340034120203333} is an apocalyptic number.

It is an amenable number.

340034120203333 is a deficient number, since it is larger than the sum of its proper divisors (4658001646695).

340034120203333 is an equidigital number, since it uses as much as digits as its factorization.

340034120203333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4658001646694.

The product of its (nonzero) digits is 46656, while the sum is 31.

Adding to 340034120203333 its reverse (333302021430043), we get a palindrome (673336141633376).

The spelling of 340034120203333 in words is "three hundred forty trillion, thirty-four billion, one hundred twenty million, two hundred three thousand, three hundred thirty-three".