Search a number
-
+
340034451151 = 525571646981
BaseRepresentation
bin1001111001010111010…
…00011111011011001111
31012111200120210212100011
410330223220133123033
521032342304414101
6420113142214051
733365241100663
oct4745350373317
91174616725304
10340034451151
11121231645a6a
1255a98a24327
13260b0084165
141265a11a8a3
158ca21ed751
hex4f2ba1f6cf

340034451151 has 4 divisors (see below), whose sum is σ = 340035623704. Its totient is φ = 340033278600.

The previous prime is 340034451149. The next prime is 340034451157. The reversal of 340034451151 is 151154430043.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 151154430043 = 236571931741.

It is a cyclic number.

It is not a de Polignac number, because 340034451151 - 21 = 340034451149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340034451157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202081 + ... + 849061.

It is an arithmetic number, because the mean of its divisors is an integer number (85008905926).

Almost surely, 2340034451151 is an apocalyptic number.

340034451151 is a deficient number, since it is larger than the sum of its proper divisors (1172553).

340034451151 is an equidigital number, since it uses as much as digits as its factorization.

340034451151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1172552.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 340034451151 its reverse (151154430043), we get a palindrome (491188881194).

The spelling of 340034451151 in words is "three hundred forty billion, thirty-four million, four hundred fifty-one thousand, one hundred fifty-one".

Divisors: 1 525571 646981 340034451151