Base | Representation |
---|---|
bin | 100110101010001101101110… |
… | …0000111001001001010010011 |
3 | 1122121000210100110112100210122 |
4 | 1031110123130013021022103 |
5 | 324032413412442203210 |
6 | 3203122220223020455 |
7 | 131425023042332561 |
oct | 11524333407111223 |
9 | 1577023313470718 |
10 | 340053433553555 |
11 | 99395940080207 |
12 | 32180772a3a72b |
13 | 11798b93bb2697 |
14 | 5dd8961664a31 |
15 | 294a8845a4b55 |
hex | 13546dc1c9293 |
340053433553555 has 16 divisors (see below), whose sum is σ = 408699375651840. Its totient is φ = 271619378708832.
The previous prime is 340053433553521. The next prime is 340053433553557. The reversal of 340053433553555 is 555355334350043.
It is a cyclic number.
It is not a de Polignac number, because 340053433553555 - 222 = 340053429359251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 340053433553497 and 340053433553506.
It is not an unprimeable number, because it can be changed into a prime (340053433553557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11627666 + ... + 28553624.
It is an arithmetic number, because the mean of its divisors is an integer number (25543710978240).
Almost surely, 2340053433553555 is an apocalyptic number.
340053433553555 is a deficient number, since it is larger than the sum of its proper divisors (68645942098285).
340053433553555 is a wasteful number, since it uses less digits than its factorization.
340053433553555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16932218.
The product of its (nonzero) digits is 60750000, while the sum is 53.
The spelling of 340053433553555 in words is "three hundred forty trillion, fifty-three billion, four hundred thirty-three million, five hundred fifty-three thousand, five hundred fifty-five".
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