Base | Representation |
---|---|
bin | 100110101010100011101101… |
… | …0011111111111011011101011 |
3 | 1122121012022020010202221120221 |
4 | 1031111013122133333123223 |
5 | 324034202113143400011 |
6 | 3203200025432030511 |
7 | 131431314120321001 |
oct | 11525073237773353 |
9 | 1577168203687527 |
10 | 340100651153131 |
11 | 99403970196680 |
12 | 3218994bb32437 |
13 | 117a047a377b0b |
14 | 5ddad60632a71 |
15 | 294bbe9a39971 |
hex | 13551da7ff6eb |
340100651153131 has 4 divisors (see below), whose sum is σ = 371018892167064. Its totient is φ = 309182410139200.
The previous prime is 340100651153119. The next prime is 340100651153171. The reversal of 340100651153131 is 131351156001043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 340100651153131 - 229 = 340100114282219 is a prime.
It is a super-2 number, since 2×3401006511531312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340100651153101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15459120506950 + ... + 15459120506971.
It is an arithmetic number, because the mean of its divisors is an integer number (92754723041766).
Almost surely, 2340100651153131 is an apocalyptic number.
340100651153131 is a deficient number, since it is larger than the sum of its proper divisors (30918241013933).
340100651153131 is a wasteful number, since it uses less digits than its factorization.
340100651153131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30918241013932.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 340100651153131 in words is "three hundred forty trillion, one hundred billion, six hundred fifty-one million, one hundred fifty-three thousand, one hundred thirty-one".
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