340111142142133 has 4 divisors (see below), whose sum is σ = 340609108675968. Its totient is φ = 339613175608300.

The previous prime is 340111142142091. The next prime is 340111142142157. The reversal of 340111142142133 is 331241241111043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-340111142142133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340111142142095 and 340111142142104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340111142146133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248983265893 + ... + 248983267258.

It is an arithmetic number, because the mean of its divisors is an integer number (85152277168992).

Almost surely, 2^{340111142142133} is an apocalyptic number.

It is an amenable number.

340111142142133 is a deficient number, since it is larger than the sum of its proper divisors (497966533835).

340111142142133 is an equidigital number, since it uses as much as digits as its factorization.

340111142142133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 497966533834.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 340111142142133 its reverse (331241241111043), we get a palindrome (671352383253176).

The spelling of 340111142142133 in words is "three hundred forty trillion, one hundred eleven billion, one hundred forty-two million, one hundred forty-two thousand, one hundred thirty-three".