Base | Representation |
---|---|
bin | 110001011111100010100… |
… | …111011100101111110001 |
3 | 110001010212222102121111121 |
4 | 301133202213130233301 |
5 | 421210444001421223 |
6 | 11122241541142241 |
7 | 500502644356144 |
oct | 61374247345761 |
9 | 13033788377447 |
10 | 3401121123313 |
11 | 10a1453230671 |
12 | 46b1b06ba981 |
13 | 1b8955506704 |
14 | ba887d3605b |
15 | 5d70e79715d |
hex | 317e29dcbf1 |
3401121123313 has 4 divisors (see below), whose sum is σ = 3510834707968. Its totient is φ = 3291407538660.
The previous prime is 3401121123307. The next prime is 3401121123343. The reversal of 3401121123313 is 3133211211043.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3401121123313 - 213 = 3401121115121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3401121123343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54856792281 + ... + 54856792342.
It is an arithmetic number, because the mean of its divisors is an integer number (877708676992).
Almost surely, 23401121123313 is an apocalyptic number.
It is an amenable number.
3401121123313 is a deficient number, since it is larger than the sum of its proper divisors (109713584655).
3401121123313 is a wasteful number, since it uses less digits than its factorization.
3401121123313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109713584654.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 3401121123313 its reverse (3133211211043), we get a palindrome (6534332334356).
The spelling of 3401121123313 in words is "three trillion, four hundred one billion, one hundred twenty-one million, one hundred twenty-three thousand, three hundred thirteen".
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