Base | Representation |
---|---|
bin | 110001011111110101000… |
… | …101101001110011111011 |
3 | 110001011200120120112222101 |
4 | 301133311011221303323 |
5 | 421212112320443120 |
6 | 11122332411404231 |
7 | 500513426502202 |
oct | 61376505516373 |
9 | 13034616515871 |
10 | 3401431031035 |
11 | 10a15a2161954 |
12 | 46b278453677 |
13 | 1b89a479306b |
14 | ba8b7168239 |
15 | 5d72bab190a |
hex | 317f5169cfb |
3401431031035 has 4 divisors (see below), whose sum is σ = 4081717237248. Its totient is φ = 2721144824824.
The previous prime is 3401431030973. The next prime is 3401431031111. The reversal of 3401431031035 is 5301301341043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3401431031035 - 229 = 3400894160123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3401431030994 and 3401431031012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340143103099 + ... + 340143103108.
It is an arithmetic number, because the mean of its divisors is an integer number (1020429309312).
Almost surely, 23401431031035 is an apocalyptic number.
3401431031035 is a deficient number, since it is larger than the sum of its proper divisors (680286206213).
3401431031035 is an equidigital number, since it uses as much as digits as its factorization.
3401431031035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680286206212.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 3401431031035 its reverse (5301301341043), we get a palindrome (8702732372078).
The spelling of 3401431031035 in words is "three trillion, four hundred one billion, four hundred thirty-one million, thirty-one thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •