Base | Representation |
---|---|
bin | 110001011111111001010… |
… | …100100010100101000001 |
3 | 110001011212112012022022011 |
4 | 301133321110202211001 |
5 | 421212234010324213 |
6 | 11122343425412521 |
7 | 500515251210415 |
oct | 61377124424501 |
9 | 13034775168264 |
10 | 3401502042433 |
11 | 10a1629253860 |
12 | 46b29819a141 |
13 | 1b89b63c7041 |
14 | ba8c2770d45 |
15 | 5d732e3c03d |
hex | 317f9522941 |
3401502042433 has 16 divisors (see below), whose sum is σ = 3844306267200. Its totient is φ = 2981272866880.
The previous prime is 3401502042353. The next prime is 3401502042439. The reversal of 3401502042433 is 3342402051043.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-3401502042433 is a prime.
It is a super-2 number, since 2×34015020424332 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3401502042395 and 3401502042404.
It is not an unprimeable number, because it can be changed into a prime (3401502042439) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7588138 + ... + 8023891.
It is an arithmetic number, because the mean of its divisors is an integer number (240269141700).
Almost surely, 23401502042433 is an apocalyptic number.
It is an amenable number.
3401502042433 is a deficient number, since it is larger than the sum of its proper divisors (442804224767).
3401502042433 is a wasteful number, since it uses less digits than its factorization.
3401502042433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15612752.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 3401502042433 its reverse (3342402051043), we get a palindrome (6743904093476).
The spelling of 3401502042433 in words is "three trillion, four hundred one billion, five hundred two million, forty-two thousand, four hundred thirty-three".
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