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340213101 = 3113404367
BaseRepresentation
bin10100010001110…
…011110101101101
3212201011121122020
4110101303311231
51144043304401
653431540353
711300522634
oct2421636555
9781147566
10340213101
11165050158
1295b2a6b9
135563a637
143328051b
151ed03d36
hex14473d6d

340213101 has 4 divisors (see below), whose sum is σ = 453617472. Its totient is φ = 226808732.

The previous prime is 340213073. The next prime is 340213151. The reversal of 340213101 is 101312043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 340213101 - 27 = 340212973 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340213151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56702181 + ... + 56702186.

It is an arithmetic number, because the mean of its divisors is an integer number (113404368).

Almost surely, 2340213101 is an apocalyptic number.

It is an amenable number.

340213101 is a deficient number, since it is larger than the sum of its proper divisors (113404371).

340213101 is a wasteful number, since it uses less digits than its factorization.

340213101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113404370.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 340213101 is about 18444.8665216097. The cubic root of 340213101 is about 698.0989923994.

Adding to 340213101 its reverse (101312043), we get a palindrome (441525144).

The spelling of 340213101 in words is "three hundred forty million, two hundred thirteen thousand, one hundred one".

Divisors: 1 3 113404367 340213101