34040441121 has 4 divisors (see below), whose sum is σ = 45387254832. Its totient is φ = 22693627412.

The previous prime is 34040441089. The next prime is 34040441131. The reversal of 34040441121 is 12114404043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34040441121 - 2⁵ = 34040441089 is a prime.

It is a super-3 number, since 3×34040441121³ (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34040441091 and 34040441100.

It is not an unprimeable number, because it can be changed into a prime (34040441131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5673406851 + ... + 5673406856.

It is an arithmetic number, because the mean of its divisors is an integer number (11346813708).

Almost surely, 2^34040441121 is an apocalyptic number.

It is an amenable number.

34040441121 is a deficient number, since it is larger than the sum of its proper divisors (11346813711).

34040441121 is a wasteful number, since it uses less digits than its factorization.

34040441121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11346813710.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 34040441121 its reverse (12114404043), we get a palindrome (46154845164).

The spelling of 34040441121 in words is "thirty-four billion, forty million, four hundred forty-one thousand, one hundred twenty-one".