Search a number
-
+
340412104433 = 1916711776023
BaseRepresentation
bin1001111010000100010…
…01000111111011110001
31012112122220102122020202
410331002021013323301
521034130444320213
6420214432444545
733410505100652
oct4750211077361
91175586378222
10340412104433
11121405838515
1255b833a9755
13261403a013b
1412694345529
158cc544ab58
hex4f42247ef1

340412104433 has 4 divisors (see below), whose sum is σ = 340414072128. Its totient is φ = 340410136740.

The previous prime is 340412104421. The next prime is 340412104481. The reversal of 340412104433 is 334401214043.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 340412104433 - 28 = 340412104177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340412104396 and 340412104405.

It is not an unprimeable number, because it can be changed into a prime (340412104133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 696341 + ... + 1079682.

It is an arithmetic number, because the mean of its divisors is an integer number (85103518032).

Almost surely, 2340412104433 is an apocalyptic number.

It is an amenable number.

340412104433 is a deficient number, since it is larger than the sum of its proper divisors (1967695).

340412104433 is a wasteful number, since it uses less digits than its factorization.

340412104433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1967694.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 340412104433 its reverse (334401214043), we get a palindrome (674813318476).

The spelling of 340412104433 in words is "three hundred forty billion, four hundred twelve million, one hundred four thousand, four hundred thirty-three".

Divisors: 1 191671 1776023 340412104433